Sunday, August 14, 2011
Friday, December 31, 2010
Friday, November 26, 2010
Ch 14_2 #2
Ch 14_1 #2
Ch 14_1 #1
Ch 13_3 #4
Ch 13_3 #3
Ch 13_3 #1
Ch 13_2 #4
Ch 13_2 #2
Ch 13_2 #1
Sunday, November 21, 2010
Ch 13_1 #4
Tuesday, November 16, 2010
Ch 12_3 #4
For part b) use relationship for energy and temperature and not that you asked to calculate the energy per one atom. Does the number you obtain is very small or big? Does it make sense?
Ch 12_3 #3
Ch 12_3 #2
Ch 12_3 #1
Monday, November 15, 2010
Ch 11_3 #3
3 comments:
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Can someone help out? I have no idea how to do this problem
- November 14, 2010 8:05 PM
- matt said...
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I cant figure this one out....Help please
- November 15, 2010 12:46 PM
Ch 11_3 #4
Part B you have to use continuity equation and Bernoulli's principle to find the pressure in the lower pipe. Then calculate the pressure in the water column.
11 comments:
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What is the continuity equation professor?
- November 13, 2010 5:42 PM
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the continuity equation is A1v1=A2v2
I'm not sure which equations to use for part A? - November 13, 2010 8:01 PM
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How the hell do you figure out anything for this question? You aren't given any pressures for any part of the pipe, just areas and velocities. How can you figure out the height or even the exiting force of the water?
- November 14, 2010 8:06 PM
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Part A: pressure of anything exited in air is just atmospheric pressure (Patm)=1.013 kPa.
- November 14, 2010 10:30 PM
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Alright so I used Bernoulli's for part A, got an answer of 145.2 kPa, says incorrect, however when I plug that into part B, and got an answer, THAT was correct?
- November 14, 2010 11:15 PM
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P(atm)=1.013*10^5 Pa
- November 15, 2010 8:21 PM
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i have no idea how to do part b
- November 15, 2010 8:52 PM
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how do we do this. This is frustrating
- November 15, 2010 8:53 PM
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Thank you to all who post answers! These questions are complicated and without help from the professor, or help in the form of really General hints, they suck.
- November 15, 2010 9:16 PM
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i still cant figure out part A..can anyone help with that?
- November 15, 2010 9:16 PM
Sunday, November 14, 2010
Friday, November 12, 2010
Ch 11_3 #2
Ch 11_3 #1
Then find the speed of the flow.
Sunday, November 7, 2010
Ch 11_2 #2
Ch 11_1 #4
Friday, November 5, 2010
Friday, October 29, 2010
Wednesday, October 27, 2010
Sunday, October 24, 2010
Ch9 3 #4
Ch9 3 #1
Wednesday, October 20, 2010
Ch9 2 #2
Monday, October 18, 2010
Tuesday, October 12, 2010
Ch8 3 #1
Ch8 2 #2
Ch8 1 #4
Ch8 1 #3
Ch8 1 #2
Wednesday, October 6, 2010
Ch7 2 #4
Ch7 1 #3
Tuesday, September 28, 2010
Ch6_3 #4
Ch6_3 #3
Ch6_2 #3
Ch6_1 #1
Part A: Is there a displacement x here ?
Part B,C: Make a sketch. Watch the angle ! The work is on the boy.
Sunday, September 26, 2010
Ch5_3 #3
See Ch 5 Sheet 12. Replace the circle shown by the equator and visualize the man standing on the equator. The pole is the center of the circle. The man is held in orbit by the Centripetal Force which is the vector sum of the Normal Force by the earth on the man and the gravitational force . Write down this vector equation paying attention to the relative signs of the vectors. The apparent weight is the Normal Force.
Ch5_3 #2
CH5_3 #1
Ch5_2 #4
Part B: See Ch 5 Sheet 17. The problem here is, as in the notes, with no friction and only the horizontal component of the Normal Force, exerted by the road on the car, supplying the centripetal force.
Ch5_2 #3
Saturday, September 25, 2010
Ch5_2 #2
See Sheet 12 and replace the box at the bottom with the ball, held in orbit by the Centripetal Force which is the vector sum of the tension in the string and the gravitational force at the bottom of the circle. Write down this vector equation paying attention to the relative signs of the vectors. The apparent weight is the force of the support on the object, the tension in the string. Take the direction of the centripetal force as positive. Solve for the speed.
Ch5_2 #1
See Sheet 12 and replace the box at the top with the car inside the circle, held in orbit by the Centripetal Force which is the vector sum of the Normal Force by the track and the gravitational force at the top of the circle. Write down this vector equation paying attention to the relative signs of the vectors. The apparent weight is the Normal Force. Set it equal to the regular weight ("true" weight). Take the direction of the centripetal force as positive. Solve for the speed. Watch out , the diameter of the loop-the-loop is given, not the radius.
Ch5_1 #3
Ch5_1 #2
Don't forget that the problem asks for an answer between 0 and 2pi.
Ch5_1 #1
Part A: You can leave the "rev" and simply divide the two given quantities, the # of rev and the rev/sec.
Part B: Use Sheet 4.
Wednesday, September 22, 2010
Tuesday, September 21, 2010
Ch5_3 #3
which spins about an axis through the center of the circle and perpendicular to the paper plane. Visualize the black rectangle being the person standing on the equatuator. On Sheeet 12 the expression Wapparent = m(g-a_c) with the vectors g and a_c is a generally valid expression for any relative orientation of the vectors. In the case of the person on the equator the vectors g and a_c are parallel to each other, i.e. the expression without vector signs is Wapparent = m(g-a_c) where g and a_c are now magnitudes of the accelerations. At the pole there is no rotation and thus no centripetal acceleration a_c and Wapparent = mg there. For Part B you take the difference between mg and Wapparent at the equator.
You have to calculate a_c as given on Sheet 4 using the circumference of the equator and the daily period of rotation.
Tuesday, September 14, 2010
Ch4_3 #3
The tensions are active as shown below:
Add the force vector components with their appropriate sign (!) to yield a net x-component = 0 and net y-component = 0 (see Ch 3 Sheet 6 extended to 3 vectors).
Ch4_3 #2
with the exception that here friction is included. ("Kinetic" friction refers to a moving object sliding on a surface, "static" friction refers to an object at rest on a surface. We do not distinguish between the two in this course and simply refer to friction.) Watch out how you use the labels m1 and m2 relative to the question here when you inspect equations in Example 4.3 ! The easiest way to proceed is to add the frictional force to the parallel weight component in the equation at the bottom of Sheet 23 with the correct sign (!) and solve for the mass asked for.
The expression obtained there is the application of Newton's Law II for the combined system (m1 + m2). I recommend strongly to study the procedure on Sheet 21 which yields the tension T in addition to the acceleration a (e.g. in case the tension T is asked for.)
Ch4_3 #1
Ch4_2 #4
Warning! To simply use the solution on Sheet 28 to get the coefficient of friction will work for you but would be a silly short cut. You will be required in the exam to understand the equations on Sheet 26, so study Example 4.4!
Ch4_2 #3
Ch4_2 #2
Part B: does the given velocity matter ?
Ch4_2 #1
Ch4_1 #2
Ch4_1 #1
The vectors in Mastering Physics are treated as done in Ch 3_1 #4 (bottom):
In order to manipulate the vector F
1. Click on vector F
2. Click “add vector”
3. Select “unlabelled vector”
4. With the cross hair draw a vector on top of F
6. Manipulate the vector you drew
Lab 3 Prep #1
It is essentially the sketch for horizontal launch in Ch 3 Sheet 25'. See Ch 3 Sheet 19 (the equations for Projectile Motion). The first 3 entries are all given. Customize them for the situation here (horizontal launch.)
For the 4th entry consult the Introduction in the Lab 3 Manual. You should, however, be able to derive this relation from your previous correct entries.
Monday, September 13, 2010
Lab 2 Prep #7
Lab 2 Prep #6
Lab 2 Prep #4,5
Notice that the blue curve is the position x as a function of time:x = x(t), and that x(t) given on Sheet 7 is an example similar to the blue curve. Consult Sheet 5 for the slopes. Consult Sheet 13 and 14 for the expressions giving x(t) and v(t). Notice further that the acceleration is positive and constant.
Sunday, September 12, 2010
Ch3_3 #4
Part A:
How do you judge whether the ball clears the net ? Think in terms of the y-component of the ball position at the location of the net. Can you calculate its value ?
(Hint: get the flight time first from the x-equations after you have identified all the given quantities for the horizontal motion. Then use it to calculate the vertical position of the ball at the net.)
Ch3_3 #3
Part A:
Visualize in the example on Sheet 21 y0 = 0 for the case here (the golf ball is hit from the ground.) Can you calculate the y-component of the initial velocity from the data given ? What do you know about the y-component of the velocity at the top of the trajectory ? Given those two can you get the rise-time by going "shopping" among the y-equations ? What do you think is the relation of the rise-and fall-time and thus the total flight time ?
Part B:
Can you get the horizontal distance from Part A and going "shopping" among the x-equations ?
Part C:
If you followed the hints in Part A you found the equation which gave you the flight time. Did it contain the gravitational acceleration ? What is then the flight time on the moon ? What would the horizontal distance be for that flight time ?
Ch3_3 #2
Part A:
What is the y-component of the initial velocity when the rifle is aimed horizontally (See Ch 3 Sheet 25') ? Go "shopping" among the y-equations to get the "sinking-time" the bullet takes to traverse the change in the y-component of the position.
Part B:
Go "shopping" among the x-equations to get the x-component of the initial velocity.
Is the speed, i.e. the magnitude of the full initial velocity vector, different from only the x-component of the initial velocity ?
Ch3_3 #1
See Ch 3 Sheet 25': Visualize the plane attached to the horizontal blue launch vector. When you drop the package what is the initial velocity of the package (magnitude and direction: notice that the package flies with the same velocity vector as the plane). Get the fall-time from the "appropriate" y-equations for the "sinking" motion in the vertical direction (go "shopping" among the equations).
Then get the horizontal distance between the point on the ground where the package was launched and the point on the ground where the package landed from the "appropriate" x-equation (go "shopping" among the equations).
Ch3_2 #4
Part A and B:
See the example Quiz 3.3 on Sheet 25'. Does the fall - time depend on the horizontal component of the initial velocity ?
Part C and D:
Once you have the fall-time how do you get the horizontal distance ?
Ch3_2 #3
of this problem. The ducks head at a appropriate angle into the wind, such that they actually fly due South. (If you rotate the figure on Sheet 16 or 16''' by 180 degrees you have the directions as given in the problem here.) The solid vectors give the velocity vectors relative to the ground, i.e. Vbg ("b" for bird) is the velocity vector pointing where the birds actually goe - not where they head which is the direction of the dashed velocity vector Vbw ("w" for wind). Identify the 2 given velocity vectors in your problem, make the sketch as on Sheet 16''' and place the velocity values given into the sketch. As is describesd on Sheet 16'' the triangle with a right angle in it allows the application of your "SOHCAHTOA" right away to get the angle, without going through the detailed setup of the vector equations on Sheet 16'. Notice that you need your calculator set to degrees in order to get the angle in degrees as asked for.
Ch3_2 #2
See the sketch on Ch 3 Sheet 16''' on the right side of the sheet (there is no video for that sheet): in your problem Mary heads the boat straight across the river, which flows east and thus pushes Mary downstream. (The solid vectors give the velocity vectors relative to the ground, i.e. Vbg is the velocity vector pointing where Mary actually goes - not where she heads the boat which is the direction of the dashed velocity vector Vbw). Identify the 2 given velocity vectors in your problem, make the sketch as on Sheet 16''' and place the velocity values given into the sketch. Notice that d is the change of position in the y-diredtion. Thus you need to use the velocity in the y-direction to get the crossing time.
Part B:
Notice that the distance downstream is the change of position in the x-diredtion. Thus you need to use the velocity in the x-direction to get the distance downstream.
Thursday, September 9, 2010
Ch3_2 #1
Ch3_1 #4
1. Click on vector A
2. Click “add vector”
3. Select “unlabelled vector”
4. With the cross hair draw a vector on top of A
5. Repeat the same for B
6. Add Vector
7. Select D and draw it
Sunday, August 29, 2010
Ch2: Comments on Lecture Notes only
Ch1: Comments on Lecture Notes only
Lab 1 #6
Lab 1 #5
Lab 1 #4
Is the absolute error given valid for the radius ? What is the power n in equation (1.8) in your case ? Is the error given divided by the diameter valid for the relative error of the radius ? Is the relative error of r^3 the same as the relative error of[(4/3 pi) r^3] (see equation (1.3)) ?
Lab 1 #3
Perimeter: Is your propagation for an addition/subtraction or multiplication/didvision ? Are the errors given for length and width absolute or relative ?
Area: Is your propagation for an addition/subtraction or multiplication/didvision ? Can you use the errors given in your propagation formula as they are or do you have to convert them ?
Ch2_3 #4
Part C: Assume the ball starts from ground. What is the velocity at the highest point of the tyravel ? See Ch2 Sheet 13 for the equation which gives you the rise time. Solve for the rise time. Is the rise time different from the fall time ?
Write the equation for the solution of the rise time down twice, for the earth and for the moon and get the ratio of the two times.
Ch2_3 #3
The acceleration of the elevator is the sum of the motor and gravitational acceleration, the net acceleration.
Part A: See Ch2 Sheet 15 to get the accelaration distance d1.
Part B: Do d1 and d2 in the sketch differ ? Get the distance d in the sketch where the elevator moves with constant velocity from the total distance, d1 and d2. Get the time t in the sketch from d and the constant velocity.
See Sheet 13 to get the acceleration time t1. Do t1 and t2 in the sketch differ ?
Get the total time.
Ch2_3 #2
See Ch2 Sheet 21 which describes the travel of the ball launched upward and then back to the level of the students hand. What is the only acceleration present ? Is this acceleration the same at any given time of the travel ?
Part B:
See Sheet 22. After the ball A, launched upward, has reached the students hand again, what is its velocity at that point, magnitude and direction, compared to the initial velocity when ball B is launched downward ?
What do you conclude then about the velocities of ball A and B when they reach the ground ?
Ch2_3 #1
she has to stop after she has traveled d2. See Sheet 15 and get the distance traveled while decelerating. Do you have all input variables to calculate the stopping distance (x-x0) ? What is your criterion when judging whether she can stop ?
Ch2_2 #3
Part B: The fraction of x of y = x/y. g is the gravitational acceleration.
Part C: See sheet 14. Do you know v0, a and t ?
Part D; if you don't know the value of units google them.
Ch2_2 #2
Part B: See Sheet 14. What does "from rest" mean for initial velocity v0 ? How can you express the distance d traveled using x and x0 (see Sheet 15')?
Ch2_2 #1
How do you get the acceleration a from the graph including its sign (see Sheet 11) ? Once you have x0, v0 and a you get x at 2 s, 3s and (Part B) 4 s.
Part D: If the car changes direction what would the value of the velocity at that point in time be? Do you see such a point on the graph ?
Ch2_1 #4
See the Notes Ch2 Sheet 3". The blue curve is the accelerated case.
Part B: On the Sheet after Sheet 5", if you "hang" the green triangle
from the red curce (constant velocity case) you measure the constant slope. See on Sheet 5 how slope of the x-t-graph and velocity are related. The green triangle "hung" from the blue curve (accelerated case) shows you how to measure the average slope between 2 time points. Apply these slope-measurements to the 4 figures and don't forget to consider the sign (+ or -) of the slope when making your judgement.
Tuesday, August 24, 2010
Ch2_1 #3
Ch2_1 #1
Re "Significant Figures" see Ch1 Sheet 9.
For the connection between speed and distance traveled see Ch2 Sheet 4' , for velocity and displacement see Ch2 Sheet 3.
If you forgot the formula for the volume of a cylinder google it.