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Welcome to PHY 121 Blog Help. Here's how it works. For each homework question and lab report we will make a post, this will probably contain a few tips on what the problems are about and how to solve them. If you are stuck on something then instead of emailing us directly you should post a comment in reply to the relevant post. We will try to guide you through tough points and help you understand the problems and the concepts behind them.
3 comments:
Determine from question #2 what k is and put into terms of g.
i got the answer for question 2 do we just use the answer for 2 and solve for g? because ive been doing that and its not working
k = (2h/g)^0.5 (answer for 2)
g = sqrt(k)/2h (wrong answer for 3)
can someone tell me what im doing wrong??
your algebra is incorrect.
k = (2h/g)^.5
square both sides=
k^2 = 2h/g
switch k and g=
g = 2h/k^2
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