Friday, October 29, 2010
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Welcome to PHY 121 Blog Help. Here's how it works. For each homework question and lab report we will make a post, this will probably contain a few tips on what the problems are about and how to solve them. If you are stuck on something then instead of emailing us directly you should post a comment in reply to the relevant post. We will try to guide you through tough points and help you understand the problems and the concepts behind them.
3 comments:
How do we go about doing this problem using the Doppler effect?
f'=v/(v-v) *f and we plug in what exactly?
how are you supposed to figure this out?? somebody help!!!
f = f0 ((v- v0)/v ) and since v= speed of sound 340m/s so we can rewrite as (1 - v0/v)
what to reduce the freq from the whistle for you to hear. SO if whistle is at 21Hz and you hear 20hz, you need a freq of 20/21 = 1 - v0/v
So its about 1/21 of the speed of sound.
340m/s / 21 = about 16m/s
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