Part B you have to use continuity equation and Bernoulli's principle to find the pressure in the lower pipe. Then calculate the pressure in the water column.
11 comments:
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What is the continuity equation professor?
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the continuity equation is A1v1=A2v2
I'm not sure which equations to use for part A? -
How the hell do you figure out anything for this question? You aren't given any pressures for any part of the pipe, just areas and velocities. How can you figure out the height or even the exiting force of the water?
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Part A: pressure of anything exited in air is just atmospheric pressure (Patm)=1.013 kPa.
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Alright so I used Bernoulli's for part A, got an answer of 145.2 kPa, says incorrect, however when I plug that into part B, and got an answer, THAT was correct?
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P(atm)=1.013*10^5 Pa
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i have no idea how to do part b
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how do we do this. This is frustrating
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Thank you to all who post answers! These questions are complicated and without help from the professor, or help in the form of really General hints, they suck.
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i still cant figure out part A..can anyone help with that?
3 comments:
For part A the tube is open to the air. What is the pressure in this case?
For part B
You need to find out not the absolute pressure but rather a difference in the pressure between the lower part and higher part of the tube (it is a straightforward application of Bernoulli's equation). Then this pressure is equal the gauge pressure at the bottom of the water column. Equating the two allows you to calculate the height.
Another way to look at it is that you need an extra pressure the fluid to the upper part of the pipe. This is just a difference that you can find from the Bernoulli's equation. And that difference is equal to the pressure created by the water column.
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