Welcome to PHY 121 Blog Help. Here's how it works. For each homework question and lab report we will make a post, this will probably contain a few tips on what the problems are about and how to solve them. If you are stuck on something then instead of emailing us directly you should post a comment in reply to the relevant post. We will try to guide you through tough points and help you understand the problems and the concepts behind them.
Tuesday, October 12, 2010
Ch8 3 #3
The stick isn't moving, so the sums of all forces and all torques must both be zero.
1 comment:
Anonymous
said...
Prof. Hobbs is right. Since torque must be the same on both sides, the mass of the guy on the right must be more. The idea is to use the torque equation, torque=force(perpindicular)*radius(or distance). Once you do this for the left person, you know the right person has the same torque. Just plug in the new dist. and get the force.
1 comment:
Prof. Hobbs is right. Since torque must be the same on both sides, the mass of the guy on the right must be more. The idea is to use the torque equation, torque=force(perpindicular)*radius(or distance). Once you do this for the left person, you know the right person has the same torque. Just plug in the new dist. and get the force.
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