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Monday, October 18, 2010
Ch9 1 #2
5 comments:
Anonymous
said...
can someone please help me with this problem. i cant part a which enables me to get b. i tried everything that i could think of
Remember that Amplitude= x0. This means x0 is the maximum range of the oscillation. Look at the graph to figure it out.
I'm having problems with part b. perhaps I'm doing something wrong but I thought frequency was 1/T. T should = 4 so f should = .25. This is wrong. Why?
Remember that the period is the time it takes to go one complete cycle. It's probably easiest to read the period if you pick places where the graph crosses the horizontal (=time) axis.
5 comments:
can someone please help me with this problem. i cant part a which enables me to get b. i tried everything that i could think of
Remember that Amplitude= x0. This means x0 is the maximum range of the oscillation. Look at the graph to figure it out.
I'm having problems with part b. perhaps I'm doing something wrong but I thought frequency was 1/T. T should = 4 so f should = .25. This is wrong. Why?
isnt it 1 over the period. and the period is the time for one full oscillation?
it doesnt work because i cant get the exact seconds
no matter what i try i can not get part B
Remember that the period is the time it takes to go one complete cycle. It's probably easiest to read the period if you pick places where the graph crosses the horizontal (=time) axis.
And, yes, frequency is just f = 1/T.
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