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Sunday, November 7, 2010
Ch 11_2 #3
Use formula for buoyant force
6 comments:
Anonymous
said...
I don't know what is going wrong with this problem. It seems to be the exact same as the following problem which I got with no problem. I subtracted the buoyant force from the weight of the block. Am I missing somehting?
Be careful, 100 cm^3 is NOT 1m^3 The conversion is really weird and you have to make up for it. If you look it up you will find that 100 cm^3 is actually 0.0001 m^3. Use that value in your calculations.
I feel like I'm doing everything right. calculating the buoyant force using the correct units and subtracting that from the weight of the block. I'm still getting it wrong, and I feel like the buoyant force is extremely small.
6 comments:
I don't know what is going wrong with this problem. It seems to be the exact same as the following problem which I got with no problem. I subtracted the buoyant force from the weight of the block. Am I missing somehting?
Be careful, 100 cm^3 is NOT 1m^3
The conversion is really weird and you have to make up for it.
If you look it up you will find that 100 cm^3 is actually 0.0001 m^3. Use that value in your calculations.
What formulas do we use for this problem?
Think what tension would be without alcohol. Then think what submerging the box into alcohol makes to the weight of the box.
I feel like I'm doing everything right. calculating the buoyant force using the correct units and subtracting that from the weight of the block. I'm still getting it wrong, and I feel like the buoyant force is extremely small.
Perhaps the problem with density of alcohol that you are using. It should be about 790 kg/m^3
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