Friday, November 26, 2010

Ch 14_2 #2

Use constant pressure and constant volume processes to calculate the heat. Pay attention what does the work since you need to put sign properly. For part c calculate initial and final temperatures to decide how much energy changed

9 comments:

Breveenn said...

For Part c Why did we have take delta T for and what about the internal energy?

Prof. Tsybychev said...

Internal energy is proportional to change in temperature thus knowing the change in temperature between 1 and 3 you can infer the change in the energy.

Anonymous said...

I don't understand the problem, are we suppose to use W=P(deltaV) and Pv=nRT? Or deltaU=nCvdeltaT? How are we suppose to tackle the problem?

Anonymous said...

I really dont understand why I am getting part B wrong can someone please explain to me how they did it?

Rupert said...

how do we tackle this problem? I found W using W=pdeltav. Where do i go from there

Anonymous said...

do we use atm for the pressure or do we need to convert that into something bec. im not getting the right answer.

Anonymous said...

i had 800cm3 and .1 mol and i thought i should use the equation (pv2)/nr=delta T and I got (4*800000)/(.1(.08206) which is wrong help please :)

Anonymous said...

I've tried part b several different ways. Can anyone help me figure this out?

Anonymous said...

I know the answer I got was right but the homework won't accept it because I don't have enough sig figs? How many do I need I put in everything correct and it just keeps telling me not quite