You should never attempt a projectile motion problem without having the 5 equations on the bottom half of Sheet 27 in front of you.
Part A:
Visualize in the example on Sheet 21 y0 = 0 for the case here (the golf ball is hit from the ground.) Can you calculate the y-component of the initial velocity from the data given ? What do you know about the y-component of the velocity at the top of the trajectory ? Given those two can you get the rise-time by going "shopping" among the y-equations ? What do you think is the relation of the rise-and fall-time and thus the total flight time ?
Part B:
Can you get the horizontal distance from Part A and going "shopping" among the x-equations ?
Part C:
If you followed the hints in Part A you found the equation which gave you the flight time. Did it contain the gravitational acceleration ? What is then the flight time on the moon ? What would the horizontal distance be for that flight time ?
6 comments:
how should we leave the answer for this question? distance traveled on earth? distance(moon) - distance(earth)? distance(moon)/distance(earth)? none of these seem to be working.
How much farther would it travel on the moon than on earth? this question is vague, its saying should you subtract the distances got for the moon?
For part C take your distance From the moon and divide it by the distance it would travel on earth. Remember the moon has 1/6 less gravity than earth.
For part C I can't get the right answer... I divded 540 by 157 and got 3.5 but it won't take the answer. That's the distance on the moon divided by the distance on the earth.
Correction... I get 3.4 but MP won't take the answer
It's going to be 6 times that on earth, Due to 1/6th gravitation on the moon
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