Tuesday, September 21, 2010

Ch5_3 #3

See Ch 5 Sheet 12: Replace the circle made by the airplane by the equator
which spins about an axis through the center of the circle and perpendicular to the paper plane. Visualize the black rectangle being the person standing on the equatuator. On Sheeet 12 the expression Wapparent = m(g-a_c) with the vectors g and a_c is a generally valid expression for any relative orientation of the vectors. In the case of the person on the equator the vectors g and a_c are parallel to each other, i.e. the expression without vector signs is Wapparent = m(g-a_c) where g and a_c are now magnitudes of the accelerations. At the pole there is no rotation and thus no centripetal acceleration a_c and Wapparent = mg there. For Part B you take the difference between mg and Wapparent at the equator.
You have to calculate a_c as given on Sheet 4 using the circumference of the equator and the daily period of rotation.

No comments: