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Saturday, September 25, 2010
Ch5_1 #3
See Ch5 Sheet 4 for the centripetal acceleration for part A. The velocity of the hand and thus the ball at the time of release is given. For part B see Sheet 10.
4 comments:
Anonymous
said...
I need some more help for part b. do we use the equationFc= m*(v^2/r) and if so how do we find the mass of the ball when it is in kg?
4 comments:
I need some more help for part b. do we use the equationFc= m*(v^2/r) and if so how do we find the mass of the ball when it is in kg?
Just do Fc=m(v^2/r). They give you the mass.
I'm doing that and its not working
never mind got it
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