You should never attempt a projectile motion problem without having the 5 equations on the bottom half of Sheet 27 in front of you.
See Ch 3 Sheet 25': Visualize the plane attached to the horizontal blue launch vector. When you drop the package what is the initial velocity of the package (magnitude and direction: notice that the package flies with the same velocity vector as the plane). Get the fall-time from the "appropriate" y-equations for the "sinking" motion in the vertical direction (go "shopping" among the equations).
Then get the horizontal distance between the point on the ground where the package was launched and the point on the ground where the package landed from the "appropriate" x-equation (go "shopping" among the equations).
2 comments:
Can someone help me? I'm not sure where exactly to start.
I found it easy to first calculate the time (t) of flight. To find this, use the equation on 25'. Specifically, equation 2.6. As in the example, use the positive root for the time. I calculated 2(y-y0) to be approximately -300m. Divide this by g (-9.8 m/s^2). The time (t) will be the square root of ((-300)/(-9.8)) as per equation 2.6. The distance will cancel out to leave only t. Hopefully this is a good start for anyone who is stuck without giving away the solution.
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