Tuesday, September 28, 2010
Ch6_3 #4
Se Ch 6 Sheet 15. Here in addition to gravity the frictional force in the atmosphere does work Wfr and equation (6.4) on Sheet 15 holds. See on Ch 6 Sheet 18 how you can write the same equation in terms of the total mechanical energy E = KE + PE with the conservation of E being E2 - E1 = 0. With friction the energy loss is Wfr = E2 - E1.
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3 comments:
For my question it says a 750kg object is lifted from the surface of the earth to a height of 890kg above the surface of the earth.
Is that 890kg supposed to be km?
Also not sure how to calculate KE for this problem. is it 1/2mv^2?
oops wrong problem, saw the issue on the correct thread
Am I on the right track?
It would be a change in PE which is = -G*M*m/R + G*M*m/(R+h).
Where does KE fit in?
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